2+4ix^2+mx+n=0

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Solution for 2+4ix^2+mx+n=0 equation:


Simplifying
2 + 4ix2 + mx + n = 0

Solving
2 + 4ix2 + mx + n = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 4ix2 + mx + -2 + n = 0 + -2

Reorder the terms:
2 + -2 + 4ix2 + mx + n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 4ix2 + mx + n = 0 + -2
4ix2 + mx + n = 0 + -2

Combine like terms: 0 + -2 = -2
4ix2 + mx + n = -2

Add '-1mx' to each side of the equation.
4ix2 + mx + -1mx + n = -2 + -1mx

Combine like terms: mx + -1mx = 0
4ix2 + 0 + n = -2 + -1mx
4ix2 + n = -2 + -1mx

Add '-1n' to each side of the equation.
4ix2 + n + -1n = -2 + -1mx + -1n

Combine like terms: n + -1n = 0
4ix2 + 0 = -2 + -1mx + -1n
4ix2 = -2 + -1mx + -1n

Divide each side by '4x2'.
i = -0.5x-2 + -0.25mx-1 + -0.25nx-2

Simplifying
i = -0.5x-2 + -0.25mx-1 + -0.25nx-2

Reorder the terms:
i = -0.25mx-1 + -0.25nx-2 + -0.5x-2

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